Optimal. Leaf size=142 \[ -\frac{a (a+b x)^n (a-b x)^{-n} \, _2F_1\left (1,n;n+1;\frac{a+b x}{a-b x}\right )}{n}+\frac{2^{-n-1} (2 n+1) \left (\frac{a-b x}{a}\right )^n (a+b x)^{n+1} (a-b x)^{-n} \, _2F_1\left (n,n+1;n+2;\frac{a+b x}{2 a}\right )}{n (n+1)}+\frac{(a+b x)^n (a-b x)^{1-n}}{2 n} \]
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Rubi [A] time = 0.0952356, antiderivative size = 173, normalized size of antiderivative = 1.22, number of steps used = 7, number of rules used = 4, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.174, Rules used = {105, 70, 69, 131} \[ \frac{a (a+b x)^n (a-b x)^{-n} \, _2F_1\left (1,-n;1-n;\frac{a-b x}{a+b x}\right )}{n}-\frac{a 2^n (a+b x)^n \left (\frac{a+b x}{a}\right )^{-n} (a-b x)^{-n} \, _2F_1\left (-n,-n;1-n;\frac{a-b x}{2 a}\right )}{n}+\frac{2^{-n} \left (\frac{a-b x}{a}\right )^n (a+b x)^{n+1} (a-b x)^{-n} \, _2F_1\left (n,n+1;n+2;\frac{a+b x}{2 a}\right )}{n+1} \]
Antiderivative was successfully verified.
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Rule 105
Rule 70
Rule 69
Rule 131
Rubi steps
\begin{align*} \int \frac{(a-b x)^{-n} (a+b x)^{1+n}}{x} \, dx &=a \int \frac{(a-b x)^{-n} (a+b x)^n}{x} \, dx+b \int (a-b x)^{-n} (a+b x)^n \, dx\\ &=a^2 \int \frac{(a-b x)^{-1-n} (a+b x)^n}{x} \, dx-(a b) \int (a-b x)^{-1-n} (a+b x)^n \, dx+\left (2^{-n} b (a-b x)^{-n} \left (\frac{a-b x}{a}\right )^n\right ) \int (a+b x)^n \left (\frac{1}{2}-\frac{b x}{2 a}\right )^{-n} \, dx\\ &=\frac{a (a-b x)^{-n} (a+b x)^n \, _2F_1\left (1,-n;1-n;\frac{a-b x}{a+b x}\right )}{n}+\frac{2^{-n} (a-b x)^{-n} \left (\frac{a-b x}{a}\right )^n (a+b x)^{1+n} \, _2F_1\left (n,1+n;2+n;\frac{a+b x}{2 a}\right )}{1+n}-\left (2^n a b (a+b x)^n \left (\frac{a+b x}{a}\right )^{-n}\right ) \int (a-b x)^{-1-n} \left (\frac{1}{2}+\frac{b x}{2 a}\right )^n \, dx\\ &=\frac{a (a-b x)^{-n} (a+b x)^n \, _2F_1\left (1,-n;1-n;\frac{a-b x}{a+b x}\right )}{n}-\frac{2^n a (a-b x)^{-n} (a+b x)^n \left (\frac{a+b x}{a}\right )^{-n} \, _2F_1\left (-n,-n;1-n;\frac{a-b x}{2 a}\right )}{n}+\frac{2^{-n} (a-b x)^{-n} \left (\frac{a-b x}{a}\right )^n (a+b x)^{1+n} \, _2F_1\left (n,1+n;2+n;\frac{a+b x}{2 a}\right )}{1+n}\\ \end{align*}
Mathematica [A] time = 0.131531, size = 160, normalized size = 1.13 \[ \frac{2^{-n} (a-b x)^{-n} (a+b x)^n \left (\frac{b x}{a}+1\right )^{-n} \left (n (a+b x) \left (1-\frac{b^2 x^2}{a^2}\right )^n \, _2F_1\left (n,n+1;n+2;\frac{a+b x}{2 a}\right )+a (n+1) \left (\frac{2 b x}{a}+2\right )^n \, _2F_1\left (1,-n;1-n;\frac{a-b x}{a+b x}\right )-a 4^n (n+1) \, _2F_1\left (-n,-n;1-n;\frac{a-b x}{2 a}\right )\right )}{n (n+1)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.052, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( bx+a \right ) ^{1+n}}{x \left ( -bx+a \right ) ^{n}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x + a\right )}^{n + 1}}{{\left (-b x + a\right )}^{n} x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (b x + a\right )}^{n + 1}}{{\left (-b x + a\right )}^{n} x}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x + a\right )}^{n + 1}}{{\left (-b x + a\right )}^{n} x}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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